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x^2+33.4x+210=0
a = 1; b = 33.4; c = +210;
Δ = b2-4ac
Δ = 33.42-4·1·210
Δ = 275.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33.4)-\sqrt{275.56}}{2*1}=\frac{-33.4-\sqrt{275.56}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33.4)+\sqrt{275.56}}{2*1}=\frac{-33.4+\sqrt{275.56}}{2} $
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